Question

A body of weight 2 kg is suspended as shown in figure. The tension $T_1$ in the horizontal string (in kg-wt) is

• A. $\frac{2}{\sqrt{3}}$
• B. $\frac{\sqrt{3}}{2}$
• C. $2\sqrt{3}$
• D. $2$

Answer 1

Answer: (C)

$2\sqrt{3}$

The tension in the above string can be divided into two components where the component opposite to weight will balance the weight while the component of this tension opposite to $T_1$ will be equal to $T_1$.
$T\sin \theta =2kgwt$
$T\cos \theta =T_1$
The first equation gives
$T=4kgwt$
So $T_1$ will be,
$T_1=2\sqrt{3}kgwt$