Question

A body of weight W = mg slides down a rough vertical pole with an acceleration $\frac{g}{4}$ where g is the acceleration due to gravity. What is the frictional force in terms of the weight of the body ?

• A. $\frac{W}{4}$
• B. $\frac{W}{2}$
• C. $\frac{W}{3}$
• D. $\frac{3W}{4}$

Answer 1

The correct option is D $\frac{3W}{4}$

We have,

$\begin{array}{c}mg-f=\frac{mg}{4}\\ \Rightarrow f=\frac{3mg}{4}\\ \Rightarrow f=\frac{3W}{4}\end{array}$

Hence,

Option $D$ is correct answer.