Question

A body 'P' contains $50$ electrons and $45$ protons and a body 'Q' contains $72$ electrons and $77$ protons after electrification by friction between the bodies. Find the number of electrons and protons in 'P' and 'Q' before electrification. Also find the number of electrons transferred between them.

Answer 1

Step 1: Given data:

Body P contains $50$ electrons and $45$protons.

Body Q contains $72$ electrons and $77$ protons.

Step 2: Finding the number of electrons and protons in 'P' and 'Q' before electrification:

We know that in a neutral body, the Number of electrons $=$ Number of protons.

During electrification, only valence electrons are transferred and not protons.

Before electrification,

Body P electrons will be $-50+5=-45e$.

Body Q electrons will be $-72-5=-77e$.

The transfer of electrons between P and Q is $5$.

Hence, the number of electrons is $-45$ and protons is $45$ in ‘P’, and the number of electrons is $-77$ and protons is $77$ in 'Q' before electrification.

The number of electrons transferred between them is $5$.