Question

A body released from a height falls freely towards the earth. Another body is released from the same height exactly a second later. Then the separation between the two bodies two seconds after the release of the second body is

• A. 4.9 m
• B. 9.8 m
• C. 19.6 m
• D. 24.5 m

Answer 1

The correct option is D 24.5 m

Both the bodies are falling freely with acceleration $g=9.8m/s^2$.

Equation to be used: $s=\frac{1}{2}\times g\times t^2$

The first body descends for 3 sec.

The height covered by this body is $s_1=\frac{1}{2}\times \left(9.8\right)\left(3^2\right)=44.1m$

The second body descends for 2 sec.

The height covered by this body is $s_2=\frac{1}{2}\times \left(9.8\right)\left(2^2\right)=19.6m$

Separation between the bodies is $s_1-s_2=(44.1-19.6)=24.5m$