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Question

A body slides on a frictionless surfaces A to B of the velocity of ball at A is 5 m/s. Its velocity at B is (g=10 m/s2)

A
8 m/s
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B
65 m/s
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C
25 m/s
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D
40 m/s
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Solution

The correct option is B 65 m/s
Let vB is the velocity at point B of a body mass m .
Since total mechanical energy is conserved
PEi+KEi=PEf+KEf
(i is for initial and f is for final)
So, the sum of kinetic energy (KEA) and potential energy (PEA) at point A will be equal to the sum of kinetic energy (KEB) and potential energy (PEB) at point B
PEA+KEA=PEB+KEB
m×g×2+12×m×v2A=0+12m×v2B
m×g×2+12×m×52=12m×v2B
v2B25=4g
vB=65 m/s,
(Velocity at point B=65 m/s)

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