A body started with a velocity of 20ms−1 and moving with an acceleration of 2ms−2. The distance (in m) travelled by the body in the 8th second is
A
35
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B
20
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C
12
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D
10
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Solution
The correct option is A35 Given, u=20ms−1,a=2ms−2,n=8 As we know that, the distance travelled by the body in nth sec is given as Sn=u+12a(2n−1) ⇒Sn=20+12×2(2×8−1) ⇒Sn=20+(16−1)=20+15=35m