A body started with velocity of 12m/s and moving with an acceleration of 2m/s2. The distance travelled by the body in the 8th second is
A
27m
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B
20m
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C
17m
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D
24m
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Solution
The correct option is A27m Given, u=12m/s,a=2m/s2,n=8
As we know that the distance travelled in nth second is given by Sn=u+12a(2n−1) S6th=12+12×2(2×8−1)=12+5 S6th=27m