A body started with velocity of 20ms−1 and moving with an acceleration of 2ms−2. The distance travelled by the body in the 8th second is
A
35m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
20m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
45m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
30m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A35m Given, u=20ms−1,a=2ms−2,n=8
As we know that the distance travelled by a particle in nth second is given as sn=u+12a(2n−1) ⇒s8th=20+12×2(2×8−1) ⇒s8th=20+15 ⇒s8th=35m