A body starts from point A with an initial velocity of 2ms−1 and with a constant acceleration of 52ms−2. How much distance would it have travelled when the velocity has reached 10ms−1?
A
965m
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B
945m
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C
925m
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D
905m
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Solution
The correct option is A965m Given:
Initial velocity, u=2ms−1,
Final velocity, v=10ms−1,
Acceleration, a=52ms−2
Using equation of motion, v2=u2+2as 102=22+2×52×s s=965m
Note that the velocity is positive throughout, hence the resultant displacement is equal to the distance travelled. Hence, the distance travelled is 965m.