Question

A body starts from point A with an initial velocity of $2m{s}^{-1}$ and with a constant acceleration of $\frac{5}{2}m{s}^{-2}$. How much distance would it have travelled when the velocity has reached $10m{s}^{-1}$?

• A. $\frac{90}{5}m$
• B. $\frac{92}{5}m$
• C. $\frac{94}{5}m$
• D. $\frac{96}{5}m$

Answer 1

The correct option is D $\frac{96}{5}m$

Given:
Initial velocity, $u=2m{s}^{-1},$
Final velocity, $v=10m{s}^{-1},$
Acceleration, $a=\frac{5}{2}m{s}^{-2}$

Using equation of motion,
$v^2=u^2+2as$
${10}^2=2^2+2\times \frac{5}{2}\times s$
$s=\frac{96}{5}m$

Note that the velocity is positive throughout, hence the resultant displacement is equal to the distance travelled. Hence, the distance travelled is $\frac{96}{5}m$.