A body starts from rest and has an acceleration $20 c m / s^{2}$ . What is the distance covered by the body in first $8 s$ ?

160 c m

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640 c m

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1280 c m

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1640 c m

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Solution

The correct option is B $640 c m$
Given,
Initial velocity, $u = 0$
$a = 20 c m / s^{2}$

From second equation of motion,
$s = u t + \frac{1}{2} a t^{2}$
$s = 0 \times 8 + \frac{1}{2} \times 20 \times 8^{2}$
$= 640 c m$

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A body starts from rest and has an acceleration 20 cm/s2. What is the distance covered by the body in first 8 s?

The correct option is B 640 cmGiven,Initial velocity, u=0a=20 cm/s2From second equation of motion,s=ut+12at2s=0×8+12×20×82 =640 cm

A body starts from rest and has an acceleration $20 c m / s^{2}$ . What is the distance covered by the body in first $8 s$ ?

The correct option is B $640 c m$
Given,
Initial velocity, $u = 0$
$a = 20 c m / s^{2}$

From second equation of motion,
$s = u t + \frac{1}{2} a t^{2}$
$s = 0 \times 8 + \frac{1}{2} \times 20 \times 8^{2}$
$= 640 c m$