A body starts from rest and moves with a constant acceleration. Which one of the following graphs represent the variation of its kinetic energy K with the distance travelled x ?
A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C As mentioned in question, body is moving with constant acceleration, so
a=constant
Now apply the third equation of motion,
v2=u2+2as
Here, u=0&s=x
∴v2=2ax
And we know that, kinetic energy of body is given by
K=12mv2=12m×2ax=max
In the above equation, m and a are constants. Also, it's a first degree equation of K and x.
Therefore, the graph of Kvsx will be stright line passing through origin ( it will pass through origin as u=0).