A body starts from rest and travels with uniform acceleration such that it covers 8m during the 2nd second. The distance it would travel during the 5th second is
A
20m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
24m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
28m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
16m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B24m Distance travel in nth second formula is sn=u+(a2)(2n−1)
For 2nd second, s2=8=u+(a2)(2×2−1) ----- (1)
For 5th second, s5=u+(a2)(2×5−1) ----- (2)
Dividing (2) by (1) and substituting u=0, we get s5=24m