Question

A body starts to fall freely under gravity. The distances covered by it in first, second and third seconds are in ratio :

• A. $1:3:5$
• B. $1:2:3$
• C. $1:4:9$
• D. $1:5:6$

Answer 1

Answer: (A)

$1:3:5$

According to equation of motion, distance covered in $n$th sec.

$S_n=u=\frac{a}{2}(2n-1)$

$S_n=\frac{a}{2}(2n-1)$

$\therefore S_1:S_2:S_3=\{2\left(1\right)-1\}:\{2\left(2\right)-1\}:\{2\left(3\right)-1\}$

$=1:3:5$