A body travelling with a velocity of 60 ms-1 gains an acceleration of 100 ms-2. Calculate the distance travelled by the body in 15 seconds .

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Solution

Dear Student

$s = u t + \frac{1}{2} a t^{2} = 60 \times 15 + \frac{1}{2} \times 100 \times 15 \times 15 s = 900 + 11, 250 = 12, 150 m = 12.15 k m$

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