A body travels $200 c m$ in the first two seconds and $220 c m$ in the next $4$ seconds with deceleration. The velocity of the body at the end of the $7^{th}$ second is

20 c m / s

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15 c m / s

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10 c m / s

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0 c m / s

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Solution

The correct option is C $10 c m / s$
$\begin{matrix} V_{1} = V_{a r} d u r i n g 0 t o 2 sec = \frac{200}{2} c m / s = 100 c m / s V_{4} = V_{a} d u r i n g 2 t o 6 sec = \frac{220}{4} c m / s = 55 c m / s V_{4} = V_{1} + a (4 - 1) \Rightarrow a = \frac{55 - 100}{3} = - 15 c m / s^{2} V_{7} = V_{4} + a \times 3 = 55 - 45 = 10 c m / s A n s . (C) \end{matrix}$

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