A body weigh 50 g in air and 40 g in water. How much would it weight in a liquid of specific gravity 1.5?

65 g

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45 g

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30 g

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35 g

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Solution

The correct option is D 35 g
density of water $ρ_{w} = 1 g c c^{- 1}$
density of liquid $ρ_{1}$ =specific gravity of liquid X density of water
$= 1.5 \times 1$
$= 1.5 g c c^{- 1}$
If V is the volume of the body, then weight of body in water= weight of body in air - upthrust of liquid
$g = 50 g - V X ρ_{w} X g$
or V=50-40
=10 cc
Weight of body in liquid = weight of body in air upthrust of liquid
$= 50 g - V ρ_{1} g$
$50 - 10 \times 1.5$
=35 g

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