MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Problem Set

A body which ...

Question

A body which was intially at rest covers a distance of $30 m$ in first 3 seconds. What is the acceleration? [3 MARKS]

Open in App

Solution

Acceleration : 3 Marks

Distance covered is given by:
$s = u t + \frac{a t^{2}}{2}$
where:
$u :$ Initial velocity
$a :$ Acceleration
30 = $0 \times 3 + \frac{9 a}{2}$
Acceleration a = $6.66 m / s^{2}$

Suggest Corrections

thumbs-up

3

Similar questions

A body which is intially at rest covers a distance of 6 m in 4 seconds. Calculate:
(a) The acceleration
(b) The final velocity [3 MARKS]

Q. A body starts from rest under uniform acceleration. If distance covered by it in

3^{r d}

3 m

, then the distance covered in

5^{t h}

Q. A body starts from rest and moves with a uniform acceleration. The ratio of the distance covered in the

n^{t h}

second to distance covered in n seconds is

Q. A body starts from rest and has an acceleration

20 c m / s^{2}

. What is the distance covered by the body in first

8 s

?

Q. A car moving with constant acceleration covered the distance between two points

60.0 m

6.00 s

. Its speed as it passes the second point was

15.0 m / s

. At what prior distance from the first was the car at rest?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Relative Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon