A bomb at rest has mass 60 kg, It explodes and a fragment of 40 kg has kinetic energy 96 joule. Then kinetic energy of other fragment is

180 J

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190 J

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182 J

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192 J

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Solution

The correct option is C 192 J
$p_{1} = p_{2}$ from momentum conservation

$\frac{K_{2}}{K_{1}} = (\frac{p_{2}}{p_{1}})^{2} \times \frac{m_{1}}{m_{2}} = \frac{m_{1}}{m_{2}} = \frac{40}{20}$

$∴ K_{2} = K_{1} \times \frac{40}{20} = 96 \times 2 = 192 J$

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A bomb at rest has mass 60 kg, It explodes and a fragment of 40 kg has kinetic energy 96 joule. Then kinetic energy of other fragment is

The correct option is C 192 Jp1=p2 from momentum conservationK2K1=(p2p1)2×m1m2=m1m2=4020∴K2=K1×4020=96×2=192J

The correct option is C 192 J
$p_{1} = p_{2}$ from momentum conservation

$\frac{K_{2}}{K_{1}} = (\frac{p_{2}}{p_{1}})^{2} \times \frac{m_{1}}{m_{2}} = \frac{m_{1}}{m_{2}} = \frac{40}{20}$

$∴ K_{2} = K_{1} \times \frac{40}{20} = 96 \times 2 = 192 J$