A stationary bomb of mass $250 k g$ suddenly explodes in two fragments in proportion of $1 : 4$ . If kinetic energy of small fragments is $360 J$ , Find the kinetic energy of large fragment.

360 J

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180 J

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1440 J

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0 J

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Solution

The correct option is C $1440 J$
given,

$250 = 1 : 4$

$\Rightarrow x + 4 x = 250 \Rightarrow x = 50$

Therefore the mass of small fragment is $50 k g$

the mass of large fragment is $200 k g$

the kinetic energy of small fragment is given by,

$K E = \frac{1}{2} m v^{2}$

$360 = \frac{1}{2} \times 50 \times v^{2}$

$∴ v^{2} = 14.4$

$K E = \frac{1}{2} m v^{2}$

$= \frac{1}{2} \times 200 \times 14.4$

Therefore the kinetic energy of large fragment is,

$= 1440 J$

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A stationary bomb of mass 250 kg suddenly explodes in two fragments in proportion of 1:4. If kinetic energy of small fragments is 360 J, Find the kinetic energy of large fragment.

The correct option is C 1440 Jgiven,250=1:4⇒x+4x=250⇒x=50Therefore the mass of small fragment is 50kgthe mass of large fragment is 200kgthe kinetic energy of small fragment is given by,KE=12mv2360=12×50×v2∴v2=14.4KE=12mv2=12×200×14.4Therefore the kinetic energy of large fragment is,=1440J

A stationary bomb of mass $250 k g$ suddenly explodes in two fragments in proportion of $1 : 4$ . If kinetic energy of small fragments is $360 J$ , Find the kinetic energy of large fragment.