A bomber is flying horizontally with a constant speed of 150 m/s at a height of 78.4 m. The pilot has to drop a bomb at the energy target. At what horizontal distance from the target should be release the bomb
A
Zero
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B
300 m
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C
600 m
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D
750 m
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Solution
The correct option is C 600 m Since the bomber drops the bomb from a height of 78.4m, the time taken for the bomb to reach the ground will be given by s=ut+12at2 where,
u is the initial velocity in the vertical direction which is 0
s is the vertical displacement from the ground which is −78.4m
a is the acceleration due to gravity g=−9.8ms−2
Upon substituting these values we get t=4s
Since the flight is moving in the horizontal direction with a speed of 150m/s, the distance covered by the bomb in the horizontal direction by the time it reaches the ground is given by (150∗4)m which is equal to 600m
∴The bomb should be released 600m away from the target