A bond that does not exist in diborane is:

B-H

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B-B

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B-H-B

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H-B-H

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Solution

The correct option is C B-B
In diborane, there is no direct bonding between two boron atom.

The bond between two boron takes place through H atom.

Option B is correct.

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H_{2} O

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(B_{2} H_{6})

The correct statement with regard to $H_{2}^{+}$ & $H_{2}^{-}$ is

l i m h \to 0 \frac{f (2 h + 2 + h^{2}) - f (2)}{f (h - h^{2} + 1) - f (1)}, (g i v e n t h a t f^{^{'}} (2) = 6 a n d f^{^{'}} (1) = 4)

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