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Question

A book of mass 0.5kg is lifted vertically upward by using energy of 1J. The vertical distance through which book is raised:


A

40cm

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B

100cm

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C

50cm

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D

20cm

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Solution

The correct option is D

20cm


Step 1: Given

Vertical distance,h=?

Mass of book, m=0.5kg

Acceleration due to gravity, g=10ms-2

Potential energy, P.E.=1J

Step 2: Mathematical expression for potential energy:

PotentialEnergy=mass×accelerationduetogravity×heightP.E.=m×g×h

Step 3: By putting the values in the above expression, we get

P.E.=m×g×h1J=0.5kg×10ms-2×hh=1J0.5kg×10ms-2=0.2mh=0.2×100cm=20cm

Therefore, the vertical distance through which book is raised is 20cm.

Hence, the correct answer is option (D) i.e. 20cm.


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