wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A bottle of dry ammonia and a bottle of dry hydrogen chloride connected with a long tube are opened simultaneously at both ends. The white ammonium chloride ring first formed will be:

A
At the centre of the tube
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Near the hydrogen chloride bottle
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Near the ammonia bottle
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Throughout the length of the tube
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Near the hydrogen chloride bottle
When a bottle of dry HCl and NH3 are connected, HCl and NH3 react to form NH4Cl, which is white in colour. The first white ring will be formed near the bottle which contains the gas that diffuses at a lesser rate than the other.

Using Graham's law of diffusion
Rate of diffusion is inversely proportional to the molecular weight of the gas i.e rM

So, rNH3rHCl=MHClMNH3

HCl has a higher molecular weight than ammonia and so will diffuse at a lesser rate than ammonia. Hence the first ring will be formed near the HCl bottle.

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The ideal gas model
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon