Question

A box contains $12$ different black balls, $7$ different red balls and $6$ different blue balls. In how many ways can the balls be selected?

• A. $2^{25}-1$
• B. $2^{25}$
• C. $728$
• D. $727$

Answer 1

Answer: (A)

$2^{25}-1$

Total number of balls in box = 12+7+6 = 25

Number of selecting balls = $2^{25}$

But we have to remove case when no ball selected and there is only one case.

So our final answer will be $2^{25}-1$