A box contains 120 tabs. Out of 120, 30 tabs are defective. The remaining tabs need to distribute among 5 people. How many tabs will one person get?
The correct option is D 18
Total number of tabs in the box =120
Number of defective tabs =30
Number of remaining Tabs =120−30=90
Number of person among which remaining tabs will be distributed =5
Let the number of tabs a person gets be x,
x=905
⇒x=18
Therefore, one person will be get 18 tabs.