A box contains $150$ oranges. If one orange. If one orange is taken out from the box at random the probabilty of its being rotten is $0.06$ , then find the number of good oranges in the box.

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Solution

Probability of rotten mangoes $= 0.06$
let number of rotten mangoes is $x$ then
$0.06 = x \times 150$
and $x = 9$
number of good mangoes $= 150 - 9 = 141$
Probability of good mangoes $= 141 / 150 = 0.94$

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A box contains 150 oranges. If one orange. If one orange is taken out from the box at random the probabilty of its being rotten is 0.06, then find the number of good oranges in the box.

Probability of rotten mangoes =0.06 let number of rotten mangoes is x then 0.06=x×150and x=9number of good mangoes =150−9=141Probability of good mangoes =141/150=0.94

A box contains $150$ oranges. If one orange. If one orange is taken out from the box at random the probabilty of its being rotten is $0.06$ , then find the number of good oranges in the box.

Probability of rotten mangoes $= 0.06$
let number of rotten mangoes is $x$ then
$0.06 = x \times 150$
and $x = 9$
number of good mangoes $= 150 - 9 = 141$
Probability of good mangoes $= 141 / 150 = 0.94$