Question

A box contains $3$ blue, $2$ white, and $4$ red marbles.If a marble is drawn at random from the box,what is the probability that it will be

$\left(i\right)$white

$\left(ii\right)$blue

$\left(iii\right)$red

Answer 1

Total no. of marbles $=3+2+4=9$

(i) No of marbles which are white $=2$

P( marbles taken out is white)

$=\frac{\text{No. of marbles which are white}}{\text{Total no. of marbles}}=\frac{2}{9}$

(ii) blue :

P(marbles taken out are blue)

$=\frac{\text{no. of marbles which are blue}}{\text{Total no. of marbles}}$

$=\frac{3}{9}=\frac{1}{3}$

(ii) No. of marbles which are red = 4

P( marbles taken out is red)

$=\frac{\text{No. of marbles which are red}}{\text{Total no. of marbles}}$

$=\frac{4}{9}$