A box contains 5 red balls, 8 green balls and 10 pink balls. A ball is drawn at random from the box. What is the probability that the ball drawn is either red or green?

\frac{13}{23}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{10}{23}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{11}{23}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{13}{529}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{13}{23}$
Total Number of Balls $= 5 + 8 + 10 = 23$ balls
Probability of getting a red ball $= \frac{5}{23}$
Probability of getting a green ball $= \frac{8}{23}$
Probability of getting a pink ball $= \frac{10}{23}$

Then, probability of getting a red or a green ball $= \frac{5 + 8}{23} = \frac{13}{23}$

Suggest Corrections

Similar questions

Q. A box contains

7

red balls,

8

green balls, and

5

white balls. A ball is drawn at random from the box. Find the probability that the ball is white.

Q. A box contains 10 white, 6 red and 10 black balls. A ball is drawn at random from the box. What is the probability that the ball drawn is either white or red?

Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that
both balls are red.

Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that
first ball is black and second is red.

Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability. that
one of them is black and other is red

Q. There are 6 red balls & 8 green balls in a bag. 5 balls are drawn out at random & placed in a red box; the remaining 9 balls are put in a green box. What is the probability that the number of red balls in the green box plus the number of green balls in the red box is not a prime number?