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Question

 Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that 
both balls are red.
 

Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that 
first ball is black and second is red.

 Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability. that 
 one of them is black and other is red 


Solution

Total number of balls = 18, number of red balls = 8 and number  of black balls = 10
    Probability of drawing a red ball Number of red ballsTotal number of balls=818
 Similarly , probability of drawing a black ball = Number of black ballsTotal number of balls=1018
 Probability of getting both red balls = P (both balls are red)
= P (a red ball is drawn at first draw and again a red ball at second draw)
=818×818=1681

Total number of balls = 18, number of red balls = 8 and number  of black balls = 10
    Probability of drawing a red ball Number of red ballsTotal number of balls=818
 Similarly , probability of drawing a black ball = Number of black ballsTotal number of balls=1018
 P (probability of getting first ball is black and second is red)
=1018×818=2081

Total number of balls = 18, number of red balls = 8 and number  of black balls = 10
    Probability of drawing a red ball Number of red ballsTotal number of balls=818
 Similarly , probability of drawing a black ball = Number of black ballsTotal number of balls=1018
Probability of getting one black and other red ball
= P (first ball is black and second is red)
+ P (first ball is red and second is black)
=1018×818+818×1018=4081
 

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