A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, the probability that it bears a two-digit number is 0.9

True

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False

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Either

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Neither

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Solution

The correct option is A True
$T o t a l n u m b e r o f s i n g l e d i g i t n u m b e r s = 9$ .
$∴ T o t a l n u m b e r o f 2 d i g i t n o s = 90 - 1 = 81 P (e v e n t) = \frac{81}{90} = \frac{9}{10} = 0.9$

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A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, the probability that it bears a two-digit number is 0.9

The correct option is A TrueTotalnumberofsingledigitnumbers=9.∴Totalnumberof2digitnos=90−1=81P(event)=8190=910=0.9

The correct option is A True
$T o t a l n u m b e r o f s i n g l e d i g i t n u m b e r s = 9$ .
$∴ T o t a l n u m b e r o f 2 d i g i t n o s = 90 - 1 = 81 P (e v e n t) = \frac{81}{90} = \frac{9}{10} = 0.9$