A box has 7 red and 4 blue balls. Two balls are drawn at random with replacement and an event is defined as '2 red balls are drawn. Find number of favorable outcomes.
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Solution

There are 7 red and 4 blue balls. It is also given that the balls are drawn at random. First ball can be drawn in 7 ways, because there are 7 red balls, same with the second ball.

$\Rightarrow$ Total number of favorable outcomes = $7 \times 7$

= 49

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A box has 7 red and 4 blue balls. Two balls are drawn at random with replacement and an event is defined as '2 red balls are drawn. Find number of favorable outcomes. ___

There are 7 red and 4 blue balls. It is also given that the balls are drawn at random. First ball can be drawn in 7 ways, because there are 7 red balls, same with the second ball. ⇒ Total number of favorable outcomes =7×7 = 49

A box has 7 red and 4 blue balls. Two balls are drawn at random with replacement and an event is defined as '2 red balls are drawn. Find number of favorable outcomes.
___

There are 7 red and 4 blue balls. It is also given that the balls are drawn at random. First ball can be drawn in 7 ways, because there are 7 red balls, same with the second ball.

$\Rightarrow$ Total number of favorable outcomes = $7 \times 7$

= 49