A box has 7 red and 4 blue balls. Two balls are drawn at random with replacement and an event is defined as '2 red balls are drawn. Find number of favorable outcomes.

Open in App

Solution

There are 7 red and 4 blue balls. It is also given that the balls are drawn at random. First ball can be drawn in 7 ways, because there are 7 red balls, same with the second ball.

$\Rightarrow$ Total number of favorable outcomes = $7 \times 7$

= 49

Suggest Corrections

Similar questions

A box has 7 red and 4 blue balls. Two balls are drawn at random with replacement and an event is defined as '2 red balls are drawn. Find number of favorable outcomes.

___

An urn contains 7 red and 4 blue balls. Two balls are drawn at random with replacement. If the probability of getting 2 red balls is P(A), find $121 \times P (A)$ .

___

Q. An urn contains

5

- red and

6

- blue balls. Two balls are drawn at random with replacement. Find the probability of getting
(1) both red balls
(2) both blue balls
(3) one-red and one-blue ball

Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that
both balls are red.

Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability that
first ball is black and second is red.

Two balls are drawn at random with replacement from a box containing 10 black and 8 red balls. Find the probability. that
one of them is black and other is red

Q. A box contains

6

red balls and

2

black balls. Two balls are drawn at random from it without replacement. if

x

denotes the number of red balls drawn, then find

E (x)

Join BYJU'S Learning Program

A box has 7 red and 4 blue balls. Two balls are drawn at random with replacement and an event is defined as '2 red balls are drawn. Find number of favorable outcomes.

There are 7 red and 4 blue balls. It is also given that the balls are drawn at random. First ball can be drawn in 7 ways, because there are 7 red balls, same with the second ball. ⇒ Total number of favorable outcomes =7×7 = 49

There are 7 red and 4 blue balls. It is also given that the balls are drawn at random. First ball can be drawn in 7 ways, because there are 7 red balls, same with the second ball.

$\Rightarrow$ Total number of favorable outcomes = $7 \times 7$

= 49