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Standard XII

Physics

Variation of G Due to Height and Depth

A box is slid...

Question

A box is sliding on a smooth frictionless surface as shown in the figure. A particle is projected at any unknown angle w.r.t box. At the same time another particle of mass m is released from the ceiling of the block. The relative acceleration of the two particles is

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2 g

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zero

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- g

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Solution

The correct option is C zero
Acceleration of particle of mass m w.r.t. ground = g
Acceleration of particle mass (2m) w.r.t. ground = g
Thus $a_{r} = g - g = 0$

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A box is sliding on a smooth frictionless surface as shown in the figure. A particle is projected at any unknown angle w.r.t box. At the same time another particle of mass m is released from the ceiling of the block. The relative acceleration of the two particles is

The correct option is C zeroAcceleration of particle of mass m w.r.t. ground = g Acceleration of particle mass (2m) w.r.t. ground = g Thus ar=g−g=0

The correct option is C zero
Acceleration of particle of mass m w.r.t. ground = g
Acceleration of particle mass (2m) w.r.t. ground = g
Thus $a_{r} = g - g = 0$