Question

# A particle P is projected from a point on the surface of smooth inclined plane (see figure). Simultaneously another particle Q is released on the smooth inclined plane from the same position. P and Q collide after $$t = 4s$$. The speed of projection of P is:-

A
5 m/s
B
10 m/s
C
15 m/s
D
20 m/s

Solution

## The correct option is B 10 m/sRelative velocity of a particle P in the frame of Q changes linearly with time during the flight of PAcceleration of Particle P and Q along the inclined is sameAcceleration of particle P perpendicular to the incline plane $$=10\ cos60$$                                                                                                     $$=10\times\dfrac{1}{2}$$                                                                                                     $$=5\ m/sec^2$$So,$$\Rightarrow V_P-5(2)=0$$$$\therefore V_P=10\ m/sec$$Hence speed of projection of P is 10 m/sec.Physics

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