A boy of 50 kg is in a lift moving down with an acceleration 9.8 $m s^{- 2}$ . The apparent weight of the body is (g = 9.8 $m s^{- 2}$ )

50 X 9.8 N

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Zero

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50 N

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\frac{50}{9.8} N

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Solution

The correct option is B Zero
given mass of the boy $m = 50 k g$
as it is moving down acceleration $a = 9.8 \frac{m}{s^{2}}$
apparent weight $= m (g - a) = 50 (9.8 - 9.8) = 50 (0) = 0$

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A boy of mass 50 kg is standing on a weighing machine placed on the floor of a lift. The machine reads his weight in newton. What is the reading of the machine when the lift is stationary? Take $g = 9.8 m s^{- 2}$

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A boy of 50 kg is in a lift moving down with an acceleration 9.8 ms−2. The apparent weight of the body is (g = 9.8 ms−2)

The correct option is B Zerogiven mass of the boy m=50kgas it is moving down acceleration a=9.8ms2apparent weight =m(g−a)=50(9.8−9.8)=50(0)=0

A boy of 50 kg is in a lift moving down with an acceleration 9.8 $m s^{- 2}$ . The apparent weight of the body is (g = 9.8 $m s^{- 2}$ )

The correct option is B Zero
given mass of the boy $m = 50 k g$
as it is moving down acceleration $a = 9.8 \frac{m}{s^{2}}$
apparent weight $= m (g - a) = 50 (9.8 - 9.8) = 50 (0) = 0$