Question

# A boy of mass 50 kg is standing on a weighing machine placed on the floor of a lift. The machine reads his weight in newton. What is the reading of the machine when the lift is stationary? Take g=9.8 ms−2

A

Zero

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B

50 N

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C

490 N

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D

500 N

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Solution

## The correct option is D 490 N Mass of the boy, m=50 kg Acceleration due to gravity, g=9.8 ms−2 Let the weighing machine exert a normal force N on the boy in vertically upward direction. As the lift is stationary, acceleration of the boy is zero. From second law of motion, N−mg=0⇒N=mg=50×9.8=490 N The machine measures this normal force. Thus, the correct choice (c).

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