The correct option is B 200 kg-m/s
Let the velocity of the boy when he left the ground is v.
From conservation of energy theorem,
mgh=12mv2
⇒v=√2gh=√2×10×0.8
⇒v=4 m/s
Therefore, momentum transferred by the ground is,
p=mv=50×4=200 kg-m/s
Hence, option (B) is the correct answer.