A boy pulls a trolley with 6 N force at an angle of 60- from ground to move the trolley 10 m- Find the work done by the boy-A- 30 JB- 60 JC- 45 JD- 90 J

The correct option is A 30 J Work done = F × s × cos θ = 6 × 10 × cos 60^∘ Work done = 6 × 10 × 1/2 = 30 J ...

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A boy pulls a...

Question

A boy pulls a trolley with 6 N force at an angle of $60^{\circ}$ from ground to move the trolley 10m. Find the work done by the boy.

30 J

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60 J

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45 J

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90 J

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Solution

The correct option is A
30 J

Work done = F $\times$ s $\times$ cos $θ$ = 6 $\times$ 10 $\times$ $cos$ $60^{\circ}$

Work done = 6 $\times$ 10 $\times$ $\frac{1}{2}$ = 30 J

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A boy pulls a trolley with 6 N force at an angle of 60∘​ from ground to move the trolley 10m. Find the work done by the boy.

The correct option is A 30 J Work done = F × s × cos θ = 6 × 10 × cos 60∘​ Work done = 6 × 10 × 12 = 30 J

A boy pulls a trolley with 6 N force at an angle of $60^{\circ}$ from ground to move the trolley 10m. Find the work done by the boy.

The correct option is A
30 J

Work done = F $\times$ s $\times$ cos $θ$ = 6 $\times$ 10 $\times$ $cos$ $60^{\circ}$

Work done = 6 $\times$ 10 $\times$ $\frac{1}{2}$ = 30 J