Question

A boy pushes a box of mass $2\text{kg}$ with a force of $\overrightarrow{F}=(20\hat{i}+10\hat{j})\text{N}$ on a frictionless surface. If the box was initially at rest, then __________$\text{m}$ is the displacement along the $x-$axis after $10\text{s}$.

Answer 1

Given:
$\overrightarrow{F}=(20\hat{i}+10\hat{j})\text{N}$
$m=2\text{kg}$

So, acceleration,
$\overrightarrow{a}=\frac{\overrightarrow{F}}{m}=\frac{20\hat{i}+10\hat{j}}{2}=(10\hat{i}+5\hat{j}){\text{m/s}}^2$

Now,
${\overrightarrow{S}}_x={\overrightarrow{u}}_{x}t+\frac{1}{2}{\overrightarrow{a}}_x{t}^2$

$\Rightarrow {\overrightarrow{S}}_x=0\times 10+\frac{1}{2}\times 10\times {10}^2$

$\Rightarrow {\overrightarrow{S}}_x=500\text{m}$