A boy standing at top of a tower of 20 m height drops a stone. Assuming g=10m/S2. The velocity with which it hits the ground is???

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Solution

H=20m

g=10m/s^2

u=0

v^2-u^2 = 2gh

v^2-0=21020

v = 20 m/s^2

Remember the formula v=√(2gh)

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A boy standing at top of a tower of 20 m height drops a stone. Assuming g=10m/S2. The velocity with which it hits the ground is???

H=20m g=10m/s^2 u=0 v^2-u^2 = 2gh v^2-0=2*10*20 v = 20 m/s^2 Remember the formula v=√(2gh)

H=20m

g=10m/s^2

u=0

v^2-u^2 = 2gh

v^2-0=21020

v = 20 m/s^2

Remember the formula v=√(2gh)