A boy travels $10 m$ due north $7 m$ due east. Find the displacement of the body.

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Solution

Here 10 m north means +y axis $10 j$ and 7m east means +x axis so $7 i$
displacement will be shortest path so 10 m and 7 m forms a right angle triangle whose hypotenuse is displacement
$\begin{matrix} d i s p l a c e m e n t = \sqrt{{(10)}^{2} + {(7)}^{2}} = \sqrt{100 + 49} = \sqrt{149} \approx 12.2 m \end{matrix}$

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A boy travels 10m due north 7m due east. Find the displacement of the body.

Here 10 m north means +y axis10j and 7m east means +x axis so 7idisplacement will be shortest path so 10 m and 7 m forms a right angle triangle whose hypotenuse is displacementdisplacement=√(10)2+(7)2=√100+49=√149≈12.2m

A boy travels $10 m$ due north $7 m$ due east. Find the displacement of the body.