Question

A man goes $10m$ due east and then $24m$ due north. Find the distance from the starting point

Answer 1

We have,

Towards North$=24$m

Towards East$=10$m

Using Pythagoras Theorem,

$(Hypotenuse{)}^2=(base{)}^2+(height{)}^2$

$=(10{)}^2+(24{)}^2$

$=100+576$

$=676$

$=(26{)}^2$

Starting point $=\sqrt{(Hypotenuse{)}^2}$

$=\sqrt{(26{)}^2}$

$=26$m

Hence, this is answer.