Question

A man goes 24m due east and then 10m due north . How far is he from his initial position

Answer 1

Draw a rough diagram according to the given data in the problem,


we get a right angled triangle ,

distance traveled towards North = 24 m

distance traveled towards East = 10 m

distance from the starting point =Joining the to end points

= Hypotenuse of the right triangle

using Pythagoras Theorem ,

( Hypotenuse )² = ( base )² + ( height )²

= ( 10 )² + ( 24 )²

= 100 + 576

= 676

= ( 26 )²

Now required distance from starting point = √ ( Hypotenuse )²

= √(26)²

= 26 m