A boy walks uniformally along the sides of a rectangular park of size 400 m× 300 m, starting from one corner to the other corner diagonally opposite. Which of the following statement is incorrect

He has travelled a distance of 700 m

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His displacement is 700 m

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His displacement is 500 m

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His velocity is not uniform throughout the walk

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Solution

The correct option is B
His displacement is 700 m

Displacement
$- - \to A C = - - \to A B + - - \to B C$
$A C = \sqrt{(A B)^{2} + (B C)^{2}} = \sqrt{(400)^{2} + (300)^{2}} = 500 m$
Distance = AB + BC = 400 + 300 = 700 m.

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A boy walks uniformally along the sides of a rectangular park of size 400 m× 300 m, starting from one corner to the other corner diagonally opposite. Which of the following statement is incorrect

The correct option is B His displacement is 700 m Displacement −−→AC=−−→AB+−−→BC AC=√(AB)2+(BC)2=√(400)2+(300)2=500 m Distance = AB + BC = 400 + 300 = 700 m.

The correct option is B
His displacement is 700 m

Displacement
$- - \to A C = - - \to A B + - - \to B C$
$A C = \sqrt{(A B)^{2} + (B C)^{2}} = \sqrt{(400)^{2} + (300)^{2}} = 500 m$
Distance = AB + BC = 400 + 300 = 700 m.