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Question
A breeder performs a dihybrid cross, where a heterozygous pea plants with yellow round seeds are self-fertilised and 800 progeny are produced. The number of progeny with yellow wrinkled seeds will be?
A breeder performs a dihybrid cross, where a heterozygous pea plants with yellow round seeds are self-fertilised and 800 progeny are produced. The number of progeny with yellow wrinkled seeds will be?
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Solution
The correct option is C 150
A dihybrid cross is a cross between two individuals that are both heterozygous for two different traits.
Heterozygous pea plant producing yellow round seeds (YyRr) were selfed. The progeny produced will be of four types phenotypically and of nine types genotypically.
The phenotypic ratio of dihybrid cross is 9:3:3:1
The proportion of yellow wrinkled is 3/16.
The total number of progeny is 800.
The number of yellow wrinkled progeny = 3/16 × 800 = 150
Therefore, 150 progeny would be possessing yellow wrinkled traits.
A dihybrid cross is a cross between two individuals that are both heterozygous for two different traits.
Heterozygous pea plant producing yellow round seeds (YyRr) were selfed. The progeny produced will be of four types phenotypically and of nine types genotypically.
The phenotypic ratio of dihybrid cross is 9:3:3:1
The proportion of yellow wrinkled is 3/16.The total number of progeny is 800.
The number of yellow wrinkled progeny = 3/16 × 800 = 150
Therefore, 150 progeny would be possessing yellow wrinkled traits.
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