In an experiment on pea plant, pure plants with yellow round seeds (YYRR) were crossed with plants producing green wrinkled seeds (yyrr). What will be phenotypic ratio of $F_{1}$ progeny?

9 yellow round : 3 round green : 3 wrinkled yellow : 1 green wrinkled

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All yellow round

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1 round yellow : 1 round green : 1 wrinkled yellow ; 1 wrinkled green

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All wrinkled green

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Solution

The correct option is B All yellow round
In an experiment, a cross is made between a homozygous plant with yellow round seeds(YYRR) is crossed with another homozygous plant with green wrinkled seeds(yyrr). In the F1 generation all progeny shows yellow round seeds(YyRr). In F1 progeny Yellow and round characters are expressed and wrinkled and green characters are not expressed. Here expressed character are dominant characters and not expressed characters are recessive characters. Mendel postulated, this explanation as Law of dominance. Due to this, all progeny in F1 are yellow round.
So, the correct option is ‘All yellow round’

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Question 5
If a round, green-seeded pea plant (RRyy) is crossed with wrinkled, yellow-seeded pea plant (rrYY), the seeds produced in F1 generation are

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In an experiment on pea plant, pure plants with yellow round seeds (YYRR) were crossed with plants producing green wrinkled seeds (yyrr). What will be phenotypic ratio of F1 progeny?

In an experiment on pea plant, pure plants with yellow round seeds (YYRR) were crossed with plants producing green wrinkled seeds (yyrr). What will be phenotypic ratio of $F_{1}$ progeny?