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Question

A bubble of air has radius 0.2 mm in water. If the bubble had been formed 20 cm below the water surface on a day when the atmospheric pressure was 1.013×105 Pa, then what would have been the total pressure inside the bubble? (surface tension of water = 73×103 N/m)

A
1.052×105 Pa
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B
1.039×105 Pa
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C
1.022×105 Pa
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D
1.152×105 Pa
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Solution

The correct option is B 1.039×105 Pa
The pressure inside the bubble will be 2Tr more than that of the outside.
Hence
Pin=Patm+ρgh+2Tr
Pin=101300+1960+730
Pin=103990 Pa
Pin=1.0399×105 Pa

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