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Standard XII

Physics

Excess Pressure in Bubbles

An air bubble...

Question

An air bubble of radius $r$ is formed at a depth $h$ below the surface of water. The pressure inside the bubble is [ $T =$ surface tension, $P_{o} =$ atmospheric pressure, $d =$ density of water]:

P_{o} = \frac{2 T}{r}

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\frac{4 T}{r} + \frac{h}{r}

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P_{o} + h d g + \frac{4 T}{r}

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P_{o} + h d g + \frac{2 T}{r}

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Solution

The correct option is D $P_{o} + h d g + \frac{2 T}{r}$
Pressure under the water at depth h is
$P^{'} = P_{O} + d g h$
Pressure inside the bubble is
$P = P^{'} + Δ P$
$P = P_{O} + d g h + \frac{2 T}{r}$

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An air bubble of radius r is formed at a depth h below the surface of water. The pressure inside the bubble is [ T= surface tension, Po= atmospheric pressure, d= density of water]:

The correct option is D Po+hdg+2TrPressure under the water at depth h is P′=PO+dghPressure inside the bubble is P=P′+ΔPP=PO+dgh+2Tr

An air bubble of radius $r$ is formed at a depth $h$ below the surface of water. The pressure inside the bubble is [ $T =$ surface tension, $P_{o} =$ atmospheric pressure, $d =$ density of water]:

The correct option is D $P_{o} + h d g + \frac{2 T}{r}$
Pressure under the water at depth h is
$P^{'} = P_{O} + d g h$
Pressure inside the bubble is
$P = P^{'} + Δ P$
$P = P_{O} + d g h + \frac{2 T}{r}$