Question

An air bubble of radius r in water is at a depth h below the water surface. If P is atmospheric pressure and d and T are the density and surface tension of water respectively. The pressure inside the bubble will be:

A
P+hdg4Tr
B
P+hdg+2Tr
C
P+hdg2Tr
D
P+hdg+4Tr

Solution

The correct option is C $$\displaystyle P+hdg+\frac{2T}{r}$$Pressure just outside the bubble will be $$P + hdg$$The $$2T/r$$ component is due to water-air interface surface tension and is additive because water exerts pressure on the bubbleSo total pressure =  $$P + hdg + 2T/r$$Physics

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